Gary Novak 1. quick proof

Second Proof Power gets Absurd at the High Velocity of a Rocket The erroneous definition of energy has a velocity problem. First, squaring velocity creates a problem in the kinetic energy formula (½mv²). Then power becomes absurd at high velocities. Power of rocket payload as rate of change in ½mv²
The horizontal line is the power of the rocket engine. Rockets are usually constant powered, meaning they use fuel at a constant rate. Power is rate of energy addition. Mathematically, the power of the rocket mass and exhaust mass are added to create the constant power. But there is a problem with that analysis. As velocity increases, it reaches a point where the power added to the payload is greater power than the engine produces. When the definition of energy is corrected, power is proportional to force only, which is constant, as fuel use is constant. Calculations m_{o} = mass of rocket at start = 21kg m' = rate of mass loss = 0.01kg/s m_{t} = mass of rocket at time T = m_{o} + m't v_{e} = separation velocity of exhaust = 10^{3}m/s (pos) F = force = m'v_{e} = (0.01)(10^{3}) = 10 newtons v'_{t} = acceleration at time T = F/m_{t} v = velocity = ∫v'dt = ∫10/(m_{o}  0.01t)dt = ∫10^{3}/(100m_{o}  t)dt = 10^{3}ln(100m_{o}  t) + c(c is quantity at T = 0) c = 10^{3}ln(100m_{0}) = 7650 Shortcut Formula for Velocity: Δv = v_{e}ln(m_{0}/m_{t}) With the existing (erroneous) definition of energy, power as rate of energy addition reduces to force times velocity. With simple math, the logic is this: ½mv²/t = ½m·v/t·v = ½mav = ½Fv. The one half is dropped, because it was for averaging. More precisely: the derivative of ½mv² with respect to t = ½m(v²)' + (m)'(½v²). KE'_{p} = ½m(2vv') + 0(½v²) = mv'v = mav = Fv The force acting upon the payload (F_{p}) is the force of the engine (10 newtons) times the mass ratio (m_{p}/m_{t}). m = 21kg total, payload = 1kg
The Logic Problem The reason why the rocket payload acquires energy as power at a higher rate than the power of the rocket engine is because velocity is an element of power, when energy is defined as ½mv². This means that the rocket engine creates velocity, and then velocity becomes a source of power.
